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Flame Combustion:
Excess Air
If there is more air present
than required to provide the stoichiometric quantity of oxygen, some oxygen
will be unchanged by the combustion process and there will be additional nitrogen
in the reactants and products. For 10% excess air (110% theoretical air)
the methane reaction will be:
C H4
+ 2.20 O2 + 2.20(3.76 N2 ) Þ C O2 + 2 H2 O + 0.20 O2 +
2.20(3.76 N2 ) + Q
If there is less oxygen present than
required for complete combustion then both CO and CO2 will be present
in the products as indicated below:
CH4
+ x O2 + x(3.76 N2) Þ a
CO2 + b CO + 2 H2O + x(3.76 N2) + Q'
where
a, b provide the balance for the carbon and oxygen equations. |
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